Bash腳本通過特殊變量處理命令行參數(shù)。使用$1、$2等獲取位置參數(shù)，其中$0代表腳本名；通過"$@"或"$*"遍歷所有參數(shù)，前者保留空格分隔，後者合併為單字符串；利用getopts解析帶參數(shù)的選項（如-a、-b:value），其中選項後加冒號表示需參數(shù)值；同時注意引用變量、使用shift移動參數(shù)列表及通過$#獲取參數(shù)總數(shù)。

Handling command line arguments in Bash might seem a bit tricky if you're new to shell scripting, but once you understand the basics, it becomes pretty straightforward. The main idea is that when you run a Bash script with arguments, those values are automatically assigned to special variables like $1 , $2 , and so on.

Here's how you can work with them effectively:

Basic Usage: Accessing Positional Arguments

In any Bash script, the first argument you pass is stored in $1 , the second in $2 , and so on. For example:

 #!/bin/bash
echo "First argument: $1"
echo "Second argument: $2"

If you run this script like this:

 ./script.sh hello world

It will output:

 First argument: hello
Second argument: world

This is the most basic way to access arguments. Just keep in mind:

• $0 refers to the script name itself.
• If you reference an argument beyond what was provided (like $4 when only two were given), it will return empty.

Handling Multiple or Unknown Arguments with $@ and $*

Sometimes you don't know how many arguments someone will pass. In these cases, $@ and $* come in handy.

Both represent all the positional arguments, but behave slightly differently when quoted:

• "$@" treats each argument as a separate word — ideal for preserving spaces in arguments.
• "$*" treats all arguments as one single word.

Here's a simple loop using $@ to print all arguments:

 for arg in "$@"
do
  echo "Argument: $arg"
done

Try running it with:

 ./script.sh apple banana "pear orange"

You'll get:

 Argument: apple
Argument: banana
Argument: pear orange

This method is especially useful when writing scripts that need to handle user input flexibly.

Using getopts for Parsing Options and Flags

If your script needs to accept options like -a , -b , or even combined ones like -abc , getopts is your best bet.

Here's a quick example:

 while getopts "ab:c" opt; do
  case $opt in
    a)
      echo "Option -a triggered"
      ;;
    b)
      echo "Option -b with argument: $OPTARG"
      ;;
    c)
      echo "Option -c triggered"
      ;;
    \?)
      echo "Invalid option: -$OPTARG"
      ;;
  esac
done

Run it like this:

 ./script.sh -a -b value -c

And you'll see:

 Option -a triggered
Option -b with argument: value
Option -c triggered

A few things to note:

• The colon after b in "ab:c" means -b expects an argument.
• OPTARG holds the value of an option that requires one.
• getopts stops processing at the first non-option argument.

A Few Tips and Gotchas

There are some small details that can trip you up:

• Always quote your variables ( "$1" , "$@" ) to prevent issues with spaces in filenames or paths.
• Use shift to move through arguments if you're dealing with variable-length input.
• You can check how many arguments were passed using $# .

For example:

 echo "Number of arguments: $#"

Also, remember that Bash doesn't support long options (like --option ) natively. You'll need to handle those manually or use tools like getopt (not getopts ).

That's basically it. It's not complicated once you get used to it, but easy to mess up if you overlook quoting or index numbers.

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