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Home Backend Development Python Tutorial Python Caching mutable values

Python Caching mutable values

Jan 26, 2025 pm 04:13 PM

Python Caching mutable values

Caching dramatically accelerates processing, from CPU-level operations to database interfaces. Cache invalidation—determining when to remove cached data—is a complex challenge. This post addresses a simpler, yet insidious, caching issue.

This problem, lurking for 18 months, surfaced only when users deviated from the recommended usage pattern. The issue stemmed from a custom machine learning (ML) framework (built on scikit-learn) within my organization. This framework accesses multiple data sources frequently, necessitating a caching layer for performance and cost optimization (reducing BigQuery egress costs).

Initially, lru_cache was used, but a persistent cache was needed for static data frequently accessed during development. DiskCache, a Python library using SQLite, was chosen for its simplicity and compatibility with our 32-process environment and Pandas DataFrames (up to 500MB). An lru_cache layer was added on top for in-memory access.

The problem emerged as more users experimented with the framework. Randomly incorrect results were reported, difficult to reproduce consistently. The root cause: in-place modification of cached Pandas DataFrames.

Our coding standard dictated creating new DataFrames after any processing. However, some users, out of habit, used inplace=True, modifying the cached object directly. This not only altered their immediate results but also corrupted the cached data, affecting subsequent requests.

To illustrate, consider this simplified example using dictionaries:

from functools import lru_cache
import time
import typing as t
from copy import deepcopy

@lru_cache
def expensive_func(keys: str, vals: t.Any) -> dict:
    time.sleep(3)
    return dict(zip(keys, vals))


def main():
    e1 = expensive_func(('a', 'b', 'c'), (1, 2, 3))
    print(e1)

    e2 = expensive_func(('a', 'b', 'c'), (1, 2, 3))
    print(e2)

    e2['d'] = "amazing"

    print(e2)

    e3 = expensive_func(('a', 'b', 'c'), (1, 2, 3))
    print(e3)


if __name__ == "__main__":
    main()

lru_cache provides a reference, not a copy. Modifying e2 alters the cached data.

Solution:

The solution involves returning a deep copy of the cached object:

from functools import lru_cache, wraps
from copy import deepcopy

def custom_cache(func):
    cached_func = lru_cache(func)

    @wraps(func)
    def _wrapper(*args, **kwargs):
        return deepcopy(cached_func(*args, **kwargs))

    return _wrapper

This adds a small overhead (data duplication), but prevents data corruption.

Key Takeaways:

  • A deeper understanding of lru_cache's reference behavior.
  • Adhering to coding standards minimizes bugs.
  • Account for user deviations from best practices in the implementation. Robustness often trumps elegance.

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