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Home Java Javagetting Started How to find numbers that appear only once in an integer array

How to find numbers that appear only once in an integer array

Sep 07, 2020 pm 05:50 PM
number array

How to find numbers that appear only once in an integer array

You can use the hashMap method to achieve this. The steps are as follows:

(Video tutorial recommendation: java course)

1 , The key in the HashMap stores the number of the array array, and the value stores the number of values ????in the array;

2. Traverse the HashMap, find the key whose Value value is equal to 1, and store it in the new array temp ;

3. Assign the values ??in the array temp to num1, num2;

The code is as follows:

import java.util.Map;
import java.util.HashMap;
import java.util.Set;
public class Solution {
    public void FindNumsAppearOnce(int [] array,int num1[] , int num2[]) {
        Map<Integer,Integer> map=new HashMap();
        for(int i=0;i<array.length;i++){
            if(map.containsKey(array[i])){
                int len=map.get(array[i]);
                map.put(array[i],len+1);
            }else{
                map.put(array[i],1);
            }
        }
        int[] temp=new int[2];
        int index=0;
        Set<Map.Entry<Integer, Integer>> sm=map.entrySet();
        for (Map.Entry<Integer, Integer> entry : sm) {
            int t1=entry.getKey();
            int t2=entry.getValue();
            if(t2==1){
                temp[index++] = t1;
            }
        }
        num1[0]=temp[0];
        num2[0]=temp[1];
    }
}

For more tutorials, please visit java Getting Started Tutorial column.

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