When programming, we often encounter the need to determine whether the characters in a string are numbers (0-9) and whether the string is a number. You may use some of the methods that come with Java, or you may use other methods. Weird tricks, such as judging whether it is an integer number and forcing the string to be an integer. If it is not a number, an error will be thrown, so it is not an integer. Here I will introduce you to several implementation methods.
How to judge whether it is a number in java
1. Use Character.isDigit(char) to judge (only one can be judged Characters)
String str = "123abc"; if (!"".equals(str)) { char num[] = str.toCharArray(); //把字符串轉(zhuǎn)換為字符數(shù)組 StringBuffer title = new StringBuffer(); //使用StringBuffer類,把非數(shù)字放到title中 StringBuffer hire = new StringBuffer(); //把數(shù)字放到hire中 for (int i = 0; i < num.length; i++) { // 判斷輸入的數(shù)字是否為數(shù)字還是字符 if (Character.isDigit(num[i])) { 把字符串轉(zhuǎn)換為字符, 再調(diào)用Character.isDigit(char) 方法判斷是否是數(shù)字, 是返回True, 否則False hire.append(num[i]); // 如果輸入的是數(shù)字,把它賦給hire } else { title.append(num[i]); // 如果輸入的是字符,把它賦給title } } }
2. Use type conversion to determine
try { String str = "123abc"; int num = Integer.valueOf(str); //把字符串強(qiáng)制轉(zhuǎn)換為數(shù)字 return true; //如果是數(shù)字,返回True } catch (Exception e) { return false; //如果拋出異常,返回False }
3. Use regular expressions to determine
String str = ""; boolean isNum = str.matches("[0-9]+"); //+表示1個或多個(如"3"或"225"),*表示0個或多個([0-9]*)(如""或"1"或"22"),?表示0個或1個([0-9]?)(如""或"7") 4. 使用Pattern類和Matcher view plaincopy String str = "123"; Pattern pattern = Pattern.compile("[0-9]+"); Matcher matcher = pattern.matcher((CharSequence) str); boolean result = matcher.matches(); if (result) { System.out.println("true"); } else { System.out.println("false"); }
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