?
?
?
?
?
??
??
??
???<表 id= "table1" class="table1" border="1px">
????<tr>
?????<th>信息</th>
?????<th>msg</th>
<th>認(rèn)證碼</th>
????</tr>
????</div>
????</div>
???
???
???
?var xmlhttp;
?if (window.XMLHttpRequest) {
??xmlhttp = new XMLHttpRequest();
?} else {
??xmlhttp = new ActiveXObject("Microsoft.XMLHTTP");
?}
??if (xmlhttp.readyState == 4 && xmlhttp.status = = 200) {
???var datastr = xmlhttp.responseText;
???var dataobj = JSON.parse(datastr)
???let dataarr = [];
???for (let i in dataobj) {
????dataarr .push(dataobj[i]);
???}
???var row = table.insertRow(table.rows.length);
???var c1 = row.insertCell(0);
???c1.innerHTML = dataarr[0];
???var c2 = row.insertCell(1);
???c2.innerHTML = dataarr[1];
???var c3 = row.insertCell(2);
???c3.innerHTML = dataarr[2];
??}
?}
?xmlhttp.open("POST", "https://api.123321yun .com/api/user/login?username=test123&password=123456", true);
?xmlhttp.setRequestHeader("Content-type", "application/x-www-form-urlencoded");
?xmlhttp. send();
?
#}


1。確定要刷新 的元素 比如? id為 #cont
2。ajax不停的請(qǐng)求服務(wù)器(后端的邏輯自己寫,什么條件下需要更新內(nèi)容)
3。當(dāng)請(qǐng)求到新的內(nèi)容 就將元素#cont內(nèi)容進(jìn)行修改
就這么思路