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redis localhost:6379> sadd userlist 1 
(integer) 1 
redis localhost:6379> sadd userlist 2 
(integer) 1 
redis localhost:6379> sadd userlist 3 
(integer) 1 
redis localhost:6379> sadd userlist 4 
(integer) 1

redis localhost:6379> sadd userlist 5
(integer) 1

redis localhost:6379> set score:user:1 20 
OK 
redis localhost:6379> set score:user:2 15 
OK 
redis localhost:6379> set score:user:3 11 
OK 
redis localhost:6379> set score:user:4 24 
OK

redis localhost:6379> set score:user:5 15
OK


redis localhost:6379> set age:user:1 29 
OK 
redis localhost:6379> set age:user:2 35 
OK 
redis localhost:6379> set age:user:3 25 
OK 
redis localhost:6379> set age:user:4 31

OK

redis localhost:6379> set age:user:5 27
OK

如上redis結(jié)構(gòu)，如何實現(xiàn)sort的時候根據(jù)score倒排序，如果score相等（上麵user2和user5的score相等），那麼按照age正排序？

期望最後得到的userid排序結(jié)果為:

4

1

5

2

3

請問各位：這樣的命令該如何寫，或者有沒有比較好的解決方案