我別無(wú)選擇，只能在處理程序中呼叫獲取器的提交方法。它正在存取路由器中正確的操作方法，但是我無(wú)法將該方法傳遞給操作，即表單中定義的 method='POST 。如何存取處理程序內(nèi)的fetch.Form方法？
const fetcher = useFetcher()
const handlerLogin = useCallback(async () => {
console.log(fetcher.formMethod) //-> outputting undefined
fetcher.submit({ value: 'social' }, { method: fetcher.formMethod })
},[])
return (
<Card className={styles.loginCard}>
<fetcher.Form method='POST' action='/'>
.............. 
1
0
0
嘗試這個(gè)解決方案，將方法傳遞給 handlerLogin 函數(shù)：
const fetcher = useFetcher();
const handlerLogin = useCallback(async (formMethod) => {
fetcher.submit({ value: 'social' }, { method: formMethod });
}, []);
return (
<Card className={styles.loginCard}>
<fetcher.Form
method='POST'
action='/'
>
{/* other parts ... */}
<button onClick={() => handlerLogin(fetcher.formMethod)}>
Submit
</button>
</fetcher.Form>
</Card>
);
