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前端代碼：
if(register_flag){ //註冊資訊都正確

        //alert(typeof($('.register-form').serialize()));
        //序列化的結(jié)果:name=hesisi&account=15223306809&verification-code=2333&password=hss123456&confirm-pwd=hss123456
        $.ajax({
            type : 'POST',
            url : 'php/register.php',
            data : $('.register-form').serialize(),  //序列化的字符串
            success : function(data){
                //window.location.href = "index.html";
            },
            error : function(){
                //錯(cuò)誤信息處理
                console.log();
            }

        });            

    }

php程式碼
require 'config.php';

$data =$_POST;
//name=hesisi&account=15223306809&verification-code=2333&password=hss123456&confirm-pwd=hss123456
$arr = explode("&",$data);
$name_arr = explode("=",$arr[0]);
$account_arr = explode("=",$arr[1]);
$verifcode_arr = explode("=",$arr[2]);
$password_arr = explode("=",$arr[3]);
$confirmpwd_arr = explode("=",$arr[4]);

$name = $name_arr[1];
$account = $account_arr[1];
$verifcode = $verifcode_arr[1];
$password = $password_arr[1];
$confirmpwd = $confirmpwd_arr[1];

$mobile_code = $_SESSION['mobile_code'];

$query = "SELECT * from user WHERE user_account=".$account;
$result = mysqli_query($query);

if($verifcode != $mobile_code){//手機(jī)驗(yàn)證碼錯(cuò)誤
    exit("手機(jī)驗(yàn)證碼錯(cuò)誤！");
    return;
}else if($result){
    exit("改手機(jī)號(hào)已經(jīng)注冊！");
    return;
}else{
    $insert = "INSERT INTO user(user_name,password,user_account) VALUES(".$name.",".$password.",".$account.")";
    mysqli_query($insert);
    exit("注冊成功！");
}

這裡報(bào)錯(cuò)說，explode()第二個(gè)參數(shù)應(yīng)該是string類型，但是我穿的是陣列類型。 ajax傳過去的data是string型啊，為什麼php透過$_POST[]接受就是array型了？ data之前沒寫過php，請指教，謝謝~