I have a simple PHP form and when the form is submitted I want to show a sweet alert, I made the following code:
<script src="https://unpkg.com/sweetalert2@7.8.2/dist/sweetalert2.all.js"></script>
<?php
if(isset($_POST['submit'])){
....
...
.....
mail($to,$subject,$message,$headers);
echo "<script type='text/javascript'>";
echo "swal({
title: 'Your Message Was Sent Successfully',
type: 'success',
confirmButtonColor: '#DD6B55',
confirmButtonText: 'CLOSE',
}).then(() => {
if (result.value) {
// handle Confirm button click
} else {
// result.dismiss can be 'cancel', 'overlay', 'esc' or 'timer'
}
});";
echo "</script>";
}
?>
However, sweetalert does not appear after the form is submitted. Can anyone tell me what is wrong here? Thank you in advance
1
0
0
Because your body is empty and sweetalert appends your code to the empty body and you get an error in your console like this:
If you want to send an alert using this method, you should have something in your body.
For example, I echoed a simple span on code and it worked for me:
sssccc
<?php
if(isset($_POST['submit'])){
mail($to,$subject,$message,$headers);
// Simple span
echo '';
echo "sssccc";
}
?>
Alternatively, if you use jQuery instead of an alert like this, you can use AJAX :
sssccc
sssccc
<?php
if(isset($_POST['submit'])){
mail($to,$subject,$message,$headers);
}
?>
sssccc
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