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Thanks for the invitation.

float x = 1.1;
float y = 1.2;
int * xx = (int*)&x;
int * yy = (int*)&y;
int k = (*xx + *yy) >> 1;
float * kk = (float*)&k;
cout << *kk << endl; // 1.15 ，結(jié)果正確

I used double at first, but the output overflowed. I suddenly thought that on my computer (most computers) double is 8 bytes, and int is only 4 bytes, so just change double to float.

There are no difficulties in the code. The only one I guess is the conversion of integers and floating point numbers in binary. You will know this part if you have studied computer composition, IEEE floating point representation.

average = (a + b) * 0.5;

Off topic,
I feel like this question is actually not a programming question, it should be a brain teaser~