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Java basics, please answer.

世界只因有你 2017-06-30 09:53:33

927

public class Demo {

             public static void main(String args[]) { 
                 boolean flag = 10%2 == 1 && 10 / 3 == 0 && 1 / 0 == 0 ; 
                 System.out.println(flag ? "mldn" : "yootk") ; 
             } 
         } 
         
         代碼如上，我任務(wù)考察的是 && 符號(hào) 與 & 符號(hào)的區(qū)別，但是在最后一個(gè)  1 / 0 == 0 這個(gè)竟然能走通，而且打印出來了yootk，這個(gè)除數(shù)不是不能為零的嗎？為什么能走通呢？很是費(fèi)解，希望大神可以給解釋下，謝謝。

世界只因有你

reply all(3)

三叔2017-06-30 09:55:33 3 floor

&& and || have a short-circuit effect:
The root cause of the short-circuit effect is to improve performance

&& operator checks whether the first expression returns false. If it is false, the result must be false and no other content is checked.
|| operator checks whether the first expression returns true. If it is true, the result Must be true, no other content will be checked

 public static void main(String args[]) { 
     boolean flag = 10%2 == 1 && 10 / 3 == 0 && 1 / 0 == 0 ; 
     System.out.println(flag ? "mldn" : "yootk") ; 
 }

10%2 == 1 is false, the following content will no longer be executed