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<ul class="swiper-wrapper">
    <li class="swiper-slide">
        <img src="./images/banner-1.jpg" alt="">
        <span class="slider-text"></span>
    </li>
    <li class="swiper-slide">
        <img src="./images/banner-2.jpg" alt="">
        <span class="slider-text"></span>
    </li>
    <li class="swiper-slide">
        <img src="./images/banner-3.jpg" alt="">
        <span class="slider-text"></span>
    </li>
    <li class="swiper-slide">
        <img src="./images/banner-4.jpg" alt="">
        <span class="slider-text"></span>
    </li>
</ul>

I want to copy the li tag itself including all sub-elements to the front of the first li tag. jquery has a simple way to write it.

var swiperPic = $(".swiper-slide")
var liHtml = swiperPic.eq(swiperPic.length - 1).html()
swiperPic.eq(0).before("<li class="swiper-slide">" +  liHtml +"<li>")

What I think of is to copy all the child elements under the li tag but not the li tag itself.