PHP的一段登陸代碼
現(xiàn)在有段PHP代碼， 我要把登陸密碼設(shè)為指定的數(shù)字， 不從數(shù)據(jù)庫里面取， 大家給我看看改如何修改？


/**
?**============================================================================
?* ============================================================================
*/

$dir_name=str_replace('\\','/',dirname(__FILE__));
$admindir=substr($dir_name,strrpos($dir_name,'/')+1);
define('CMS_PATH',str_replace($admindir,'',$dir_name));
define('INC_PATH',CMS_PATH.'includes/');
define('DATA_PATH',CMS_PATH.'data/');
include(INC_PATH.'fun.php');
include(DATA_PATH.'confing.php');
include(INC_PATH.'mysql.class.php');
if(file_exists(DATA_PATH.'sys_info.php')){
include(DATA_PATH.'sys_info.php');
}
$mysql=new mysql(DB_HOST,DB_USER,DB_PASSWORD,DB_NAME,DB_CHARSET,DB_PCONNECT);
session_start();
$_SESSION['login_in']=empty($_SESSION['login_in'])?'':$_SESSION['login_in'];
$_SESSION['admin']=empty($_SESSION['admin'])?'':$_SESSION['admin'];
if($_SESSION['login_in']&&$_SESSION['admin']){header("location:admin.php");}
$action=empty($_GET['action'])?'login':$_GET['action'];
$password=empty($_POST['password'])?'':$_POST['password'];
$user=empty($_POST["user"])?'':$_POST['password'];
$code=empty($_POST['code'])?'':$_POST['code'];
$submit=empty($_POST['submit'])?'':$_POST['submit'];
go_url($action);

function login(){
global $_sys;
include('template/admin_login.html');
}
function ck_login(){
global $submit,$user,$password,$_sys,$code;
$submit=$_POST['submit'];
$user=fl_html(fl_value($_POST['user']));
$password=fl_html(fl_value($_POST['password']));
$code=$_POST['code'];
if(!isset($submit)){
msg('請從登陸頁面進(jìn)入');
}
if(empty($user)||empty($password)){
msg("密碼或用戶名不能為空");
}
if(!empty($_sys['safe_open'])){
foreach($_sys['safe_open'] as $k=>$v){
if($v=='3'){
if($code!=$_SESSION['code']){msg("驗證碼不正確！");}
}
}
}
check_login($user,$password);

}

function out(){
login_out();
}
?>


------解決方案--------------------
那你將你的check_login($user,$password);
方法的$password變量直接設(shè)置為數(shù)字就可。在方法里面就將你傳遞的數(shù)字在你的方法里面進(jìn)行比對。
------解決方案--------------------
fun.php 貼出這個文件的代碼
------解決方案--------------------

PHP code

check_login($user,$password) {
 ($password == '12345') ? $_SESSION['login_in'] = yes : die("error");
}
<br><font color="#e78608">------解決方案--------------------</font><br>
有幾個注釋的地方自己看看 因為不知道你其他代碼是否有用到那些變量處理.<br><br>

PHP code

function check_login($user, $password) {
    /*
    $rel=$GLOBALS['mysql']->fetch_asc("select id,admin_name,admin_password,admin_purview,is_disable from ".DB_PRE."admin where admin_name='".$user."' limit 0,1");
    $rel=empty($rel)?'':$rel[0];
    if(empty($rel)){
        msg('不存在該管理用戶','login.php');
    }
    $password=md5($password);

    if($rel['is_disable']){
        msg('該賬號已經(jīng)被鎖定,無法登陸');
    }
      */
    $oldPassword = '12345'; //默認(rèn)固定密碼
    if ($password != $oldPassword) {
        msg("輸入的密碼不正確");
    }

    if (!isset($_SESSION)) {
        session_start();
    }
    $_SESSION['admin'] = $rel['admin_name'];
    //$_SESSION['admin_purview'] = $rel['admin_purview']; //這里需要根據(jù)車給你需代碼進(jìn)行處理
    //$_SESSION['admin_id'] = $rel['id']; 這里id 需要根據(jù)程序代碼進(jìn)行處理
    $_SESSION['admin_time'] = time();
    $_SESSION['login_in'] = 1;
    $_SESSION['login_time'] = mktime();
    $ip = fl_value(get_ip());
    $ip = fl_html($ip);
    $_SESSION['admin_ip'] = $ip;
    //unset($rel);
    header("location:admin.php");
} <div class="clear">
                 
              
              
        
            </div>