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Home Java Javagetting Started How to determine whether a string is an IP address in java

How to determine whether a string is an IP address in java

Aug 06, 2020 pm 04:07 PM
IP address java string

How to determine whether a string is an IP address in java

要實(shí)現(xiàn)該算法我們首先應(yīng)該知道,IP地址應(yīng)該依據(jù)哪些條件:

(推薦教程:java入門教程

判斷原則:

  • 判斷該字符長度是否是7-15位之間(0.0.0.0-255.255.255.255.255)

  • 是否能以小數(shù)點(diǎn)分成四段

  • 每段是否都是數(shù)字

  • 每段數(shù)字是否都在0-255之間

只有以上四個(gè)條件都滿足了,才是IP的正確格式。

實(shí)現(xiàn)該算法有兩種比較簡單的方法,一種是常規(guī)判斷,另一種是利用正則表達(dá)式進(jìn)行判斷,下面以函數(shù)的形式實(shí)現(xiàn)這兩種方法,可以直接復(fù)制函數(shù)使用,傳入的參數(shù)是待判斷的字符串,返回的是布爾變量。

(視頻教程推薦:java視頻教程

常規(guī)方法判斷

//判斷字符是否是IP
public boolean isCorrectIp(String ipString) {
        //1、判斷是否是7-15位之間(0.0.0.0-255.255.255.255.255)
	if (ipString.length()<7||ipString.length()>15) {
		return false;
	}
	//2、判斷是否能以小數(shù)點(diǎn)分成四段
	String[] ipArray = ipString.split("\\.");		
	if (ipArray.length != 4) {
		return false;
	}
	for (int i = 0; i < ipArray.length; i++) {
		//3、判斷每段是否都是數(shù)字
		try {
			int number = Integer.parseInt(ipArray[i]);
			//4.判斷每段數(shù)字是否都在0-255之間
			if (number <0||number>255) {
        			return false;
			}
		} catch (Exception e) {
			return false;
		}
	}		
	return true;
	}

正則表達(dá)式方法判斷

//利用正則表達(dá)式判斷字符是否為IP
public boolean isCorrectIp2(String ipString) {
	String ipRegex = "\\d{1,3}\\.\\d{1,3}\\.\\d{1,3}\\.\\d{1,3}";	//IP地址的正則表達(dá)式
	//如果前三項(xiàng)判斷都滿足,就判斷每段數(shù)字是否都位于0-255之間
	if (ipString.matches(ipRegex)) {
		String[] ipArray = ipString.split("\\.");
		for (int i = 0; i < ipArray.length; i++) {
			int number = Integer.parseInt(ipArray[i]);
			//4.判斷每段數(shù)字是否都在0-255之間
			if (number <0||number>255) {
				return false;
			}
		}
		return true;
	}
	else {
		return false;	//如果與正則表達(dá)式不匹配,則返回false
	}	
}

測試結(jié)果:

How to determine whether a string is an IP address in java

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