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The PHP web page generates a QR code, and the Android client scans the code to log in.

大家講道理

Nov 08, 2016 am 11:41 AM

使用了Github上具有掃碼功能的ZXing開源庫(kù)，使用了通過隨機(jī)數(shù)生成二維碼圖片網(wǎng)絡(luò)API，整個(gè)過程經(jīng)過三步：
1.PHP網(wǎng)頁(yè)生成二維碼，相應(yīng)隨機(jī)數(shù)存儲(chǔ)到數(shù)據(jù)庫(kù)中；
2.Android客戶端掃碼，攜帶username保存至隨機(jī)數(shù)對(duì)應(yīng)的位置；

3.每隔一段時(shí)間，PHP通過Ajax輪詢數(shù)據(jù)庫(kù)，判斷是否為空，不為空則跳轉(zhuǎn)網(wǎng)頁(yè)。

<html>
  <head>
    <title>qrlogin</title>
    <meta charset="UTF-8"/>
  </head>
  <body>
    <?php
    /**
     * @author Cenquanyu
     * @version 2016年5月12日
     *
     */
       require &#39;mysql_connect.php&#39;;
       $randnumber = "";
       for($i=0;$i<8;$i++){
       $randnumber.=rand(0,9);
       }
       //將生成的隨機(jī)數(shù)保存至數(shù)據(jù)庫(kù)
       mysql_query("insert into login_data (randnumber) values (&#39;$randnumber&#39;)")
        
    ?>
     
   <img  src="/static/imghw/default1.png"  data-src="http://qr.liantu.com/api.php?text=<?php echo $randnumber;? alt="The PHP web page generates a QR code, and the Android client scans the code to log in." >"  class="lazy"   width="300px"/>
   <input hidden="hidden" type="text" name="randnumber" id="randnumber"value="<?php echo $randnumber;?>"/>
  
  </body>
  <script>
    xmlHttpRequest.onreadystatechange = function(){
       if(xmlHttpRequest.status == 200 && xmlHttpRequest.readyState ==4){
    result = xmlHttp.responseText;
    if(result==true){//username不為空則跳轉(zhuǎn)頁(yè)面
         window.location.href=&#39;welcome.php&#39;;
    }
}
}
  }
  function polling(){
 
      //執(zhí)行輪詢操作
      var xmlHttpRequest;
      if(window.XMLHttpRequest){
          xmlHttpRequest = new XMLHttpRequest();
          }
      else{
          xmlHttpRequest = new ActiveXObject("Microsoft.XMLHTTP");
      }
       randnumber = document.getElementById(&#39;randnumber&#39;).value;
       xmlHttpRequest.open("GET","polling.php?randnumber="+ randnumber,true);
       xmlHttpRequest.send();
  }
       setInterval("polling()",1000);
</script>
 
</html>

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