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Home Backend Development PHP Tutorial PHP 使用編碼樹,生成easyui中的tree樣式

PHP 使用編碼樹,生成easyui中的tree樣式

Jun 23, 2016 pm 01:38 PM

?生成樹的時候,數(shù)據(jù)庫中一般設(shè)計的都為無級數(shù),即為:父子節(jié)點的樹,例如:基本的數(shù)據(jù)表設(shè)計為:

nodecode 節(jié)點編碼

parentnodecode 父節(jié)點編碼

nodename ?節(jié)點名稱

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這樣的形式,在生成樹的時候,根據(jù)子找父,再找爺爺?shù)年P(guān)系,一直找到最頂級,來確定一個從屬關(guān)系,如果由父級找子級再找孫子級,那么,就可以有無限個孩子級,所以這種情況,適合不限分類的一種寫法,但是這種寫法帶來的結(jié)果就是,效率比較低,處理的時間長,所以在開發(fā)過程中,就出現(xiàn)了一種編碼樹的形式:基本的數(shù)據(jù)表設(shè)計為:

nodecode 節(jié)點編碼

nodename 節(jié)點名稱

這種編碼樹,子節(jié)點,帶著父節(jié)點的信息,比如說節(jié)點編碼為:001 名稱為:1級 節(jié)點編碼為:001001 名稱為:1_1級,從此可以看出,我只要看到001001就能知道他的父級是誰,也能知道他的子集是誰,在數(shù)據(jù)庫中只要使用 likt '001001%',即可得到,以nodecoder的長度為varchar(30)為例,則最多產(chǎn)生10個子集,即001001001001001001001001001001這樣的關(guān)系,如果以3位長度為一個節(jié)點的長度,則可產(chǎn)生999個同級分類,如果以4個節(jié)點長度,則可產(chǎn)生9999個節(jié)點,所以隨著每個節(jié)點的長度的增長,可以容納更多的節(jié)點和子集,此適合不是無限級分類的使用。

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使用無級樹,在網(wǎng)上有許多生成easyui中tree使用Json的方法,下面這樣方法是根據(jù)編碼生生成json的方式,僅為簡單的一個實現(xiàn):

 1     public function getTree($root,$text="typename",$value="typecode", $fileLength = 3) { 2         $childNode = array(); 3 foreach ($root as $key=>$node) { 4 unset($childNode); 5 foreach ($root as $k => $v) { 6 if ($this->startWith($v["typecode"], $node["typecode"]) && $v["typecode"] != $node["typecode"]) { 7 $childNode[] = $v; 8  } 9  } 10 $treeNode = array(); 11 if (strlen($node["typecode"]) == $fileLength) { 12 $treeNode['children'] = $this->getTree($childNode,$text,$value, $fileLength + 3); 13 $treeNode["id"] = $node[$value]; 14 $treeNode["text"] = $node[$text]; 15 $treeNode["value"] = $node[$value]; 16 $treeNode["checked"] = "false"; 17 // $node["attributes"] = $node; 18 $treeNode["state"] = "open"; 19 $tree[] = $treeNode; 20  } 21  } 22 return $tree; 23  } 24 private function startWith($str, $needle) { 25 return strpos($str, $needle) === 0; 26 }

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