php中判斷文件空目錄是否有讀寫權(quán)限的函數(shù)代碼
Jun 13, 2016 am 11:58 AM
is_writable用來處理,記住 PHP 也許只能以運(yùn)行 webserver 的用戶名(通常為 \'nobody\')來訪問文件。不計(jì)入安全模式的限制。
Example #1 is_writable() 例子
復(fù)制代碼 代碼如下:
$filename = 'test.txt';
if (is_writable($filename)) {
echo 'The file is writable';
} else {
echo 'The file is not writable';
}
?>
上面的函數(shù)有一個(gè)問題就是filename 必需。規(guī)定要檢查的文件 ,必須是文件啊,目錄不可判斷,下面我們來判斷空目錄。
實(shí)例1
該功能非常常用,特別在一些需要生成靜態(tài)文件的項(xiàng)目中,一個(gè)目錄是否可以,關(guān)乎到是否對(duì)該目錄有創(chuàng)建文件刪除文件的權(quán)限
復(fù)制代碼 代碼如下:
/*
問題出現(xiàn):如何檢查一個(gè)目錄是否可寫,如何目錄下還有目錄和文件,那么都要檢查
思路:
(1)首先先寫出檢查空目錄是否可寫的算法:
在該目錄中生成一個(gè)文件,如果不能生成,表明該目錄沒有寫的權(quán)限
(2)使用遞歸的辦法來進(jìn)行檢查
代碼實(shí)現(xiàn):
*/
set_time_limit(1000);
function check_dir_iswritable($dir_path){
$dir_path=str_replace('\','/',$dir_path);
$is_writale=1;
if(!is_dir($dir_path)){
$is_writale=0;
return $is_writale;
}else{
$file_hd=@fopen($dir_path.'/test.txt','w');
if(!$file_hd){
@fclose($file_hd);
@unlink($dir_path.'/test.txt');
$is_writale=0;
return $is_writale;
}
$dir_hd=opendir($dir_path);
while(false!==($file=readdir($dir_hd))){
if ($file != "." && $file != "..") {
if(is_file($dir_path.'/'.$file)){
//文件不可寫,直接返回
if(!is_writable($dir_path.'/'.$file)){
return 0;
}
}else{
$file_hd2=@fopen($dir_path.'/'.$file.'/test.txt','w');
if(!$file_hd2){
@fclose($file_hd2);
@unlink($dir_path.'/'.$file.'/test.txt');
$is_writale=0;
return $is_writale;
}
//遞歸
$is_writale=check_dir_iswritable($dir_path.'/'.$file);
}
}
}
}
return $is_writale;
}
上面實(shí)例主要是fopen去在目錄創(chuàng)建文件或在文件中寫內(nèi)容,這樣就可以判斷目錄的讀寫權(quán)限了。

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