This concise example demonstrates how jQuery's $.map() function efficiently retrieves values from an array of JavaScript objects. The array contains day-price pairs; the goal is to find the price associated with a specific day.
var dayArr = [
{ "day": "day01", "price": "0" },
{ "day": "day02", "price": "0" },
{ "day": "day03", "price": "0" }
];
var findDay = 'day02'; // Target day
var price = $.map(dayArr, function(value, key) {
if (value.day == findDay) {
return value.price;
}
});
console.log(price); // Output: 0
jQuery Array Search: Frequently Asked Questions
This section addresses common questions regarding jQuery's array search capabilities.
Q: How does jQuery.inArray() function?
A: jQuery.inArray() searches for a specific value within an array. If found, it returns the value's index; otherwise, it returns -1. It uses strict equality (===), requiring both value and type to match.
Q: jQuery.inArray() vs. JavaScript's indexOf()?
A: Both locate values in arrays. jQuery.inArray() supports array-like objects, while indexOf() only works with arrays. jQuery.inArray() offers an optional starting index parameter, unlike indexOf().
Q: Checking Value Existence with jQuery.inArray()?
A: Use this pattern:
var array = [1, 2, 3, 4, 5];
var value = 3;
if ($.inArray(value, array) !== -1) {
alert(value + " exists in the array");
} else {
alert(value + " does not exist in the array");
}
Q: jQuery.inArray() and Multidimensional Arrays?
A: jQuery.inArray() doesn't directly handle multidimensional arrays. Nested loops are necessary to search within each sub-array.
Q: Finding a Value's Index with jQuery.inArray()?
A:
var array = [1, 2, 3, 4, 5];
var value = 3;
var index = $.inArray(value, array);
if (index !== -1) {
alert("The index of " + value + " is " + index);
} else {
alert(value + " is not in the array");
}
Q: jQuery.inArray() with Objects?
A: jQuery.inArray() is unsuitable for objects. Alternative methods, like iterating through object properties, are required.
Q: Removing a Value with jQuery.inArray()?
A:
var array = [1, 2, 3, 4, 5];
var value = 3;
var index = $.inArray(value, array);
if (index !== -1) {
array.splice(index, 1);
}
Q: jQuery.inArray() with Strings?
A: Works identically to numbers.
Q: Finding All Occurrences with jQuery.inArray()?
A: jQuery.inArray() only finds the first occurrence. Looping and repeated calls are needed for all instances.
Q: jQuery.inArray() with Arrays of Objects?
A: Direct use is impossible. Iterate through the array and compare object properties individually.
The above is the detailed content of jQuery Array Search Simple Example. For more information, please follow other related articles on the PHP Chinese website!
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