JavaScript deconstruction and assignment: simplify code and improve readability

JavaScript's deconstructed assignment allows you to extract individual elements from an array or object using concise syntax and assign them to variables, simplifying the code and making it clearer and easier to read.

Deconstruction and assignment are widely used, including processing API responses, functional programming, and in frameworks and libraries such as React. It can also be used for nested objects and arrays, default function parameters, variable value exchange, return multiple values ??from a function, for-of loops, and regular expression processing.

When using deconstructed assignments, you need to pay attention to the following points: You cannot start a statement with curly braces, because it looks like a block of code. To avoid errors, either declare the variable or use brackets if the variable is declared. Also be careful to avoid mixing declared and undeclared variables.

How to use deconstruction assignment

Deconstructing array

Suppose we have an array:

const myArray = ['a', 'b', 'c'];

Deconstruction provides an easier and less error-prone alternative to extracting each element:

const [one, two, three] = myArray;

// one = 'a', two = 'b', three = 'c'

You can ignore certain values ??by omitting the value name when assigning, for example:

const [one, , three] = myArray;

// one = 'a', three = 'c'

Or use the rest operator (...) to extract the remaining elements:

const [one, ...two] = myArray;

// one = 'a', two = ['b', 'c']

Deconstructing object

Deconstruction also applies to objects:

const myObject = {
  one:   'a',
  two:   'b',
  three: 'c'
};
// ES6 解構(gòu)示例
const {one, two, three} = myObject;
// one = 'a', two = 'b', three = 'c'

In this example, the variable names one, two, and three match the object property name. We can also assign attributes to variables of any name, for example:

const myObject = {
  one:   'a',
  two:   'b',
  three: 'c'
};

// ES6 解構(gòu)示例
const {one: first, two: second, three: third} = myObject;

// first = 'a', second = 'b', third = 'c'

Deconstruct nested objects

More complex nested objects can also be referenced, for example:

const meta = {
  title: 'Destructuring Assignment',
  authors: [
    {
      firstname: 'Craig',
      lastname: 'Buckler'
    }
  ],
  publisher: {
    name: 'SitePoint',
    url: 'https://www.sitepoint.com/'
  }
};

const {
    title: doc,
    authors: [{ firstname: name }],
    publisher: { url: web }
  } = meta;

/*
  doc   = 'Destructuring Assignment'
  name  = 'Craig'
  web   = 'https://www.sitepoint.com/'
*/

This seems a bit complicated, but remember that in all deconstructed assignments:

• The left side of the assignment is the deconstruction target - the pattern that defines the assigned variable
• To the right of the assignment is the deconstructed source - an array or object containing the extracted data

Precautions

There are some other things to note. First, you can't start the statement with curly braces, because it looks like a code block, for example:

// 這會失敗
{ a, b, c } = myObject;

You have to declare variables, for example:

// 這可以工作
const { a, b, c } = myObject;

Or use brackets if the variable has been declared, for example:

// 這可以工作
({ a, b, c } = myObject);

You should also be careful to avoid mixing declared and undeclared variables, such as:

// 這會失敗
let a;
let { a, b, c } = myObject;

// 這可以工作
let a, b, c;
({ a, b, c } = myObject);

The above are the basic knowledge of deconstruction. So, under what circumstances does it work? I'm glad you asked this question.

Deconstructed use cases

Simpler statement

Variables can be declared without explicitly defining each value, for example:

// ES5
var a = 'one', b = 'two', c = 'three';

// ES6
const [a, b, c] = ['one', 'two', 'three'];

Authentic, the deconstructed version is longer. It's easier to read, although it may not be the case for more items.

Variable value exchange

Swap values ??require a temporary third variable, but using deconstruction is much easier:

var a = 1, b = 2;

// 交換
let temp = a;
a = b;
b = temp;

// a = 2, b = 1

// 使用解構(gòu)賦值交換
[a, b] = [b, a];

// a = 1, b = 2

You are not limited to two variables; you can rearrange any number of items, such as:

const myArray = ['a', 'b', 'c'];

Default function parameters

Suppose we have a prettyPrint() function to output our meta object:

const [one, two, three] = myArray;

// one = 'a', two = 'b', three = 'c'

If there is no deconstruction, you need to parse this object to ensure that appropriate default values ??are available, for example:

const [one, , three] = myArray;

// one = 'a', three = 'c'

Now, we can assign default values ??to any parameter, for example:

const [one, ...two] = myArray;

// one = 'a', two = ['b', 'c']

But we can use deconstruction to extract values ??and assign default values ??if necessary: ??

const myObject = {
  one:   'a',
  two:   'b',
  three: 'c'
};
// ES6 解構(gòu)示例
const {one, two, three} = myObject;
// one = 'a', two = 'b', three = 'c'

I'm not sure if this is easier to read, but it's obviously shorter.

Return multiple values ??from function

The

function can only return one value, but this can be a complex object or a multidimensional array. Deconstructing assignment makes this more practical, for example:

const myObject = {
  one:   'a',
  two:   'b',
  three: 'c'
};

// ES6 解構(gòu)示例
const {one: first, two: second, three: third} = myObject;

// first = 'a', second = 'b', third = 'c'

for-of loop

Consider an array of book information:

const meta = {
  title: 'Destructuring Assignment',
  authors: [
    {
      firstname: 'Craig',
      lastname: 'Buckler'
    }
  ],
  publisher: {
    name: 'SitePoint',
    url: 'https://www.sitepoint.com/'
  }
};

const {
    title: doc,
    authors: [{ firstname: name }],
    publisher: { url: web }
  } = meta;

/*
  doc   = 'Destructuring Assignment'
  name  = 'Craig'
  web   = 'https://www.sitepoint.com/'
*/

ES6's for-of is similar to for-in, except that it extracts each value instead of index/key, for example:

// 這會失敗
{ a, b, c } = myObject;

Deconstruction assignment provides further enhancements, such as:

// 這可以工作
const { a, b, c } = myObject;

regular expression processing

Regular expression functions (such as match) return an array of matches, which can constitute the source of deconstructed assignments:

// 這可以工作
({ a, b, c } = myObject);

Further reading

• Deconstruction assignment – ??MDN
• Is there any performance loss in deconstructing assignments using JavaScript - Reddit
• for...of statement – ??MDN

Frequently Asked Questions about ES6 Deconstruction Assignment (FAQ)

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By making statement adjustments, synonyms replacement and paragraph reorganization of the original text, pseudo-original processing of the original text is completed, and the original format and location of the picture are retained.

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