


How to Successfully Deserialize JSON into a C# POCO Class Using JsonConvert.DeserializeObject?
Jan 15, 2025 am 11:42 AMUse JsonConvert.DeserializeObject to parse JSON to C# POCO class
When encountering errors (such as "Unable to deserialize..." exception) when deserializing JSON to a C# POCO class, it is crucial to understand the requirements for successful deserialization.
Specifically, the JsonConvert.DeserializeObject
method requires that the JSON conforms to the expected structure and data type defined in the POCO class.
Resolving errors
The key to solving this error lies in two aspects:
-
Correctly declare list properties: Make sure the JSON response contains an array of objects for the properties declared as
List<T>
in the POCO class. For example:{ "username": "username", // ... 其他屬性 "accounts": [ { "github": "github-username" }, // ... 其他帳戶 ] }
In a POCO class, the
Accounts
attribute should be declared as:[JsonProperty("accounts")] public List<Account> Accounts { get; set; }
-
Use JsonProperty attribute:
JsonProperty
attributes map JSON attribute names to corresponding POCO class attributes. By default, JSON property names are case-sensitive and match C# property names. To customize this mapping, use theJsonProperty
attribute:[JsonProperty("github")] public string GithubUsername { get; set; }
Example
Here is a corrected example:
public class User { [JsonProperty("username")] public string Username { get; set; } // ... 其他屬性 [JsonProperty("accounts")] public List<Account> Accounts { get; set; } } public class Account { [JsonProperty("github")] public string GithubUsername { get; set; } } // 反序列化代碼 var json = @"{ 'username': 'jdoe', // ... 其他屬性 'accounts': [{ 'github': 'jdoe-github' }] }"; var user = JsonConvert.DeserializeObject<User>(json);
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