A common question among sysadmins: "How do I quickly generate dummy CPU load on this machine?" If a simple 100% CPU load across one or more cores is sufficient, building a custom solution is surprisingly easy.
The Single-Core Solution (One-Liner)
This single line of C code, compiled and run, will peg one core at 100% utilization:
int main() {while (1) {}}
Compile using gcc -o stressme stressme.c (or cl stressme.c on Windows) and run with ./stressme (or stressme.exe). To stress multiple cores, simply run multiple instances of the program.
Multi-Core Solution (Multi-Threaded)
For more controlled multi-core stress testing, consider this multi-threaded version using 4 POSIX threads:
#include <pthread.h>
#include <unistd.h>
#define NUM_THREADS 4
void *loop(void *arg) {
while (1) {}
}
int main() {
pthread_t threads[NUM_THREADS];
for (int i = 0; i < NUM_THREADS; i++) {
pthread_create(&threads[i], NULL, loop, NULL);
}
for (int i = 0; i < NUM_THREADS; i++) {
pthread_join(threads[i], NULL);
}
return 0;
}
Compile with gcc -o multistress multistress.c -pthread.
How It Works
The core functionality is a simple infinite loop (while (1) {}). At the assembly level, this translates to a continuous jmp instruction, maximizing CPU usage. Modern preemptive multitasking operating systems allow this loop to consume processor time without rendering the system completely unresponsive; the process can still be terminated. In contrast, older cooperative multitasking systems would likely freeze due to such a loop.
global _start
_start:
jmp _startThe above is the detailed content of How to % CPU. For more information, please follow other related articles on the PHP Chinese website!
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