Why Does My Random String Generator Produce Duplicate Outputs?
Jan 05, 2025 am 11:17 AM
Random String Generator Duplicating Output
Your goal is to generate two distinct four-character random strings. However, your current code returns duplicates.
Root Cause
The root cause lies in the initialization of the Random instance within the RandomString method. Each invocation of the method creates a new instance of Random, resulting in identical sequences of random numbers.
Solution
To ensure two unique random strings, move the initialization of the Random instance outside the method, into the class level. This ensures that a single instance is used throughout the lifetime of the class.
Modified Code
private static Random random = new Random((int)DateTime.Now.Ticks);
private string RandomString(int size)
{
StringBuilder builder = new StringBuilder();
char ch;
for (int i = 0; i < size; i++)
{
ch = Convert.ToChar(Convert.ToInt32(Math.Floor(26 * random.NextDouble() + 65)));
builder.Append(ch);
}
return builder.ToString();
}
// get 1st random string
string Rand1 = RandomString(4);
// get 2nd random string
string Rand2 = RandomString(4);
// create full rand string
string docNum = Rand1 + "-" + Rand2;
Example Output
The modified code will generate two unique four-character random strings, such as:
UNTE-FWNU
instead of duplicates like:
UNTE-UNTE
By initializing the Random instance at the class level, you ensure that a consistent sequence of random numbers is used, resulting in unique random strings.
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